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245m^2-405=0
a = 245; b = 0; c = -405;
Δ = b2-4ac
Δ = 02-4·245·(-405)
Δ = 396900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{396900}=630$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-630}{2*245}=\frac{-630}{490} =-1+2/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+630}{2*245}=\frac{630}{490} =1+2/7 $
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